The Untouchables, Olate Dogs as well as David Garibaldi and His CMYK's will compete with three other acts in the finals.
- September 7, 2012
AceShowbiz -
"America's Got Talent" has announced the last finalists of its seventh season. Twelve acts had performed on Tuesday, September 4, but only three of them still stay on the show after the Thursday, September 6 episode.
Just like last week, Nick Cannon called three acts on stage each time to reveal the top four first. Shanice & Maurice Hayes, All That! and Lightwire Theater were on the first group and it's Lightwire Theater who were advancing to the top four. They were later joined by David Girabaldi & His CMYK's, Olate Dogs and the Untouchables.
The Untouchables and Olate Dogs were soon announced to be in the finals, meaning that the fates of Lightwire Theater and Girabaldi were up on the judges' hands. "Both are equally as artistic and creative. This should never have happened," Sharon Osbourne said of the two acts before landing her choice on Lightwire Theater.
Howie Mandel was rooting for Girabaldi and Howard Stern agreed with him. "I have a true gut feeling David belongs in the finals. Lightwire, I'm sorry, you're fabulous," the shock jock gave the final verdict that sent Girabaldi to the finals.
The Untouchables, Olate Dogs and Girabaldi will next compete with Joe Castillo, William Close and Tom Close on September 12.
